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You have a reaction: A + B --> C The reaction is first order with respect...

You have a reaction:

A + B --> C

The reaction is first order with respect to A and 2nd order with respect to B. If 0.8904 mol of A is mixed with 0.3749 mol of B to make a 1.000 L solution and the rate of the reaction is 0.873 M/s, what is the rate constant (k)?

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Answer #1

We can write the rate equaiton as below.

Rate = k[A][B]2

Rate =  rate of the reaction = 0.873 M/s

[A] = 0.8904 Moles

[B] = 0.3749 Moles

k = rate constant = ?

Substitute the values to find k

0.873 = k 0.8904 x 0.37492

k = 0.873 / 0.12514 = 6.975

Rate constant k = 6.975

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