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Uniform cylinder roles down a rough inclined plane without sliding. The resultant force parallel to the inclined plane is given by R and the Torque with respect to the cylinder axis given by T, out of the relationships given below what is correct , pls explain. (1) R = 0 සහ τ = 0 (2) R = 0 සහ τ ≠ 0 (3) R ≠ 0 සහ τ = 0 (4) R ≠ 0 සහ τ ≠ 0 (5) R =...
2. The ends of uniform rod AB can slide along the horizontal floor and the inclined plane. At the instant shown, the end A is moving at a constant velocity of 2.5 to the left. Using the concept of the instantaneous center of zero velocity, determine (a) the angular velocity of the rod and (b) the velocity of end B of the rod. Also determine the acceleration of the mass center of the rod, G, which is located at the...
A box of mass m is sliding down an inclined plane. The plane makes an angle ϴ with the horizontal ground. What is the magnitude of the component of the gravitational force that is parallel to the inclined plane? A. m g cosθ B. m g sinϴ C. 0 D. m g If you lift a 2 kg weight through a vertical distance of 1 m at constant velocity, how much work did you do on the weight? Assume the...
A rod A and a disks B are sliding on a horizontal plane as shown. They have a mass of my = 10 kg and mg = 3 kg respectively. When they initially collide, the rod has a velocity v2 = 5 m/s and the disk has a velocity of vo = 9 m/s in the directions shown. The coefficient of restitution is e=0.6. The coefficient of kinetic friction Hi = 0.4. (a) Assume that rod A does not spin....
A 2 kg block is sliding down a plane inclined at 30˚ to the horizontal. The coefficient of friction between the block and the plane is 0.25. How much work is done by gravity if the block slides 5 m? How much work is done by friction? If the block starts from rest, what is its speed after sliding the 5 m?
A block of mass m is sliding down a plane inclined at an angle theta to the horizontal. If the coefficient of friction is µk . Find the acceleration of the block. Draw a vector diagram to solve this question.
A block of mass 5000 gm is sliding down an inclined plane that makes an angle of 35 degrees to the ground. If the base distance of the inclined plane is 800 cm, calculate the work done when the block reaches the ground.
25. A block of mass 25 kg is sliding down an inclined plane at a speed of 5.0 m/s when it passes point A Point A is 5.0 m above the ground. The incline plane makes an angle of 46e above the horizontal. Point B is 1.5 m above the ground The coefficient of kinetic friction is 0.30. Find the speed of the block, in m/s, at point E.
The velocity of a 1.10 kg block sliding down a frictionless inclined plane is found to be 1.11 m/s. 1.90 s later, it has a velocity of 7.38 m/s. What is the angle of the plane with respect to the horizontal? Use "deg" as your units.
A block sliding down a fixed inclined plane slows to a stop. Which of the following is true? A. A change in the normal force caused the block to stop. B. The kinetic friction force was less than the component of the weight down the inclined plane. C. The kinetic friction force was greater than the component of the weight down the inclined plane. D. The static friction force overcame the kinetic friction force.