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The table below shows the profit, P(x), in dollars, from sellingx items. 2 3 6 9 14 P(x) 88.9 108 117.3 86.4 -32.7 -427.2 Usi

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Answer #1

A scatterplot of the given data is attached. The scatterplot resembles a downwards opening parabola so that the given darte represents a quadratic function.

| 100 , 2468 10 12 14

Let the quadratic function be y = P(x) = ax2+bx+c.

On substituting x = 1, we get a+b+c = 88.9…(1).

On substituting x = 3, we get 9a+3b+c = 117.3…(2) and

On substituting x = 14, we get196a+14b+c = -427.2…(3)

The augmented matrix for the above linear system is A (say) =

1

1

1

88.9

9

3

1

117.3

196

14

1

-427.2

To solve the above linear system, we have to reduce A to its RREf which is

1

0

0

-4.9

0

1

0

33.8

0

0

1

60

This implies that a = -4.9, b = 33.8 and c = 60.

Hence, P(x) = -4.9x2+33.8x+60.

When x = 8, we have P(x) = -4.9*64+33.8*8 +60 = -313.6 + 270.4+60 = 16.8.

Thus, the profit from selling 8 items is $ 16.8.

Further, when P(x) = -328.7, we have -4.9x2+33.8x+60 = -328.7 or, -4.9x2+33.8x+388.7 = 0.

A graph of the function y = -4.9x2+33.8x+388.7 is attached. It may be observed that the graph crosses the X-Axis at x = -6.1 and x = 13

Since x cannot be negative, hence 13 items have to be sold for a profit of $ -328.7.

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