I need help calculating c, cu, cm, and alpha for a vane less diffuser assuming no...
I need help calculating c, cu, cm, and alpha for a
vane less diffuser assuming no diffuser losses. My numbers for the
outlet of the turbo are U=23.561 m/s
Cm=2.8318 m/s
Cu= 1.237 m/s
r=. 45m
Cu is absolute velocity that is tangential
Cm is effective volume flow
C is magnitude of those
Alpha is the angle of the flow
Homework Answers
Answer:
The solution is given below in the fig.
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I need help calculating c, cu, cm, and alpha for a
vane less diffuser assuming no...
Honeycomb Flow Straightener - Anti-Turbulence Screens Silencer Fan Test Section Diffuser Iniet Assuming a circular cross...
Honeycomb Flow Straightener - Anti-Turbulence Screens Silencer Fan Test Section Diffuser Iniet Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10% Ns/m? (assume there are no losses in the wind tunnel) Contraction ratio: 7 Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in the test section with a manometer (manometer fluid is water...
need help with letter j,k,l,m,n,o just those i solved the top ones just the last 6...
need help with letter j,k,l,m,n,o just those i solved the top
ones just the last 6 thanjs you
mine the temperature (K) at the throat. Your Answer=289.711 Correct! Exact Answer=289.71 +/- 1.0E+00 e) Determine the velocity (m/s) at the throat. Your Answer 341.18 Correct! Exact Answer 341.183 +/- 1.3E+00 f) Determine the pressure (kPa) at the throat. Your Answer=314.09 Correct! Exact Answer=314.10 +/- 1.2E+00 g) Determine the mass flow rate (kg/s) through the nozzle Your Answer=1.0826 Correct! Exact Answer= 1.08264...
just now i sent this questions. this is the answer given. however the answer i afraid...
just now i sent this questions.
this is the answer given. however the answer i afraid
that he used formula that is not for constant surface temperature
and noncircular formula.
this is the formula foe the noncircular tube. because
the question ask about triangle.
my problem is, i cannot answer question 1(b) that ask
the heat transfer coefficient, h. please help me. thank you.
this pic is a note on constant surface temperature.
page 482
ref: HEAT AND MASS TRANSFER:...
summarizr the followung info and write them in your own words and break them into different...
summarizr the followung info and write them in your own words and break them into different key points. 6.5 Metering Chamber: 6.5.1 The minimum size of the metering box is governed by the metering area required to obtain a representative test area for the specimen (see 7.2) and for maintenance of reasonable test accuracy. For example, for specimens incorporating air spaces or stud spaces, the metering area shall span an integral number of spaces (see 5.5). The depth of...
summatize the following info and break them into differeng key points. write them in yojr own...
summatize the following info and break them into differeng key points. write them in yojr own words
apartus
6.1 Introduction—The design of a successful hot box appa- ratus is influenced by many factors. Before beginning the design of an apparatus meeting this standard, the designer shall review the discussion on the limitations and accuracy, Section 13, discussions of the energy flows in a hot box, Annex A2, the metering box wall loss flow, Annex A3, and flanking loss, Annex...
Honeycomb Flow Straightener - Anti-Turbulence Screens Silencer Fan Test Section Diffuser Iniet Assuming a circular cross section, the atmospheric pressure is 101.325 kPa, density of air is 1.2 kg/m², and absolute viscosity of air is 1.825*10% Ns/m? (assume there are no losses in the wind tunnel) Contraction ratio: 7 Diffuser length: 3 m Test section diameter = test section length = 70 cm a) When a static-pitot tube placed in the test section with a manometer (manometer fluid is water...
need help with letter j,k,l,m,n,o just those i solved the top
ones just the last 6 thanjs you
mine the temperature (K) at the throat. Your Answer=289.711 Correct! Exact Answer=289.71 +/- 1.0E+00 e) Determine the velocity (m/s) at the throat. Your Answer 341.18 Correct! Exact Answer 341.183 +/- 1.3E+00 f) Determine the pressure (kPa) at the throat. Your Answer=314.09 Correct! Exact Answer=314.10 +/- 1.2E+00 g) Determine the mass flow rate (kg/s) through the nozzle Your Answer=1.0826 Correct! Exact Answer= 1.08264...
just now i sent this questions.
this is the answer given. however the answer i afraid
that he used formula that is not for constant surface temperature
and noncircular formula.
this is the formula foe the noncircular tube. because
the question ask about triangle.
my problem is, i cannot answer question 1(b) that ask
the heat transfer coefficient, h. please help me. thank you.
this pic is a note on constant surface temperature.
page 482
ref: HEAT AND MASS TRANSFER:...
summatize the following info and break them into differeng key points. write them in yojr own words
apartus
6.1 Introduction—The design of a successful hot box appa- ratus is influenced by many factors. Before beginning the design of an apparatus meeting this standard, the designer shall review the discussion on the limitations and accuracy, Section 13, discussions of the energy flows in a hot box, Annex A2, the metering box wall loss flow, Annex A3, and flanking loss, Annex...
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