Two of the lines of the atomic hydrogen spectrum have wavelengths of 656?nm and 410?nm. If these fall at normal incidence on a grating with 8200 slits/cm,what will be the angular separation of the two wavelengths in the first-order spectrum?
apply d sin theta = mL
here d = 1/8200 = 1.219 um
for wave length 1, L1 = 656 nm
sin theta = 1* 656nm/1.219 um = 0.538
theta = 32.55 deg
for L2, sin theta = 1* 410nm/1.219 um
sin theta = 0.336
theta = 19.633 deg
angular separation is 32.55-19.633 = 12.91 deg
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