Question

Apoli ol 2,010 rankenly selected adits showed ha % of them on col phons he echniogydisplay belownsues hum atest ot to clam that92% of ais ow, cel prores o the biromial dstribuúion, and assume a 001 significance level to complete parts (a) trough( Test of p:092vs p#092 Sample X N Sample p %0% Cl 1980 2.060 0961165 (0.9502000 972130) 680 0000 Z Value P.Value a. Is the test two-tailed, left-taled, or right-taile O Twolailed test O Lelt-tailed test O Right tailed test b. What is the test statistic? The test statistic is□ Round to two decimal places as needed) C. What is the P.value? The P.value is Round to three decimal places as needed ) Click to select your answer(s) 929 cT

Answer 1

Solution:-

a) Two tailed test

b)

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: P = 0.92
Alternative hypothesis: P ? 0.92

Note that these hypotheses constitute a two-tailed test.

Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method, shown in the next section, is a one-sample z-test.

Analyze sample data. Using sample data, we calculate the standard deviation (S.D) and compute the z-score test statistic (z).

S.D = sqrt[ P * ( 1 - P ) / n ]

S,.D = 0.00598
z = (p - P) / ?

z = 6.88

where P is the hypothesized value of population proportion in the null hypothesis, p is the sample proportion, and n is the sample size.

Since we have a two-tailed test, the P-value is the probability that the z-score is less than -6.88 or greater than 6.88.

Thus, the P-value = less than 0.001

Interpret results. Since the P-value (almsot 0) is less than the significance level (0.05), we have to reject the null hypothesis.