Question

Interpret the empirical formula: Na_2SO_4 Interpret the molecular formula: Na_2SO_4

Answer 1

wavelengh of the radiation = $3.83 \AA$ = $3.83 \times 10^{-10} m$

we know that energy of 1 photon

$E = h\frac{c}{\lambda }$

where h= Planck's constant = 6.626 x 10¯³⁴ J s

c = speed of light =  3.00 x 10⁸ m/s

$\lambda$ = wavelength = $3.83 \times 10^{-10} m$

therefore putting the values E =5.19 x 10¯¹⁶ J