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You are titrating 130.0 mL of 0.050 M Ca2 with 0.050 M EDTA at pH 9.00....
A 120.0 mL sample of 0.040 M Ca2+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kr for the Ca2-EDTA comple...
A 120.0 mL sample of 0.040 M Ca2+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kr for the Ca2-EDTA complex is 10.65 and the fraction of free EDTA in the Y4 form, a, is 0.041 at pH 9.00 What is K, the conditional formation constant, for Ca2+ at pH 9.00? K What is the equivalence point volume, V, in milliliters? C Ve= mL Calculate the concentration of Ca2t at V Ca2+ М Calculate the...
A 150.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log Kr for the Ca2+-EDTA c...
A 150.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log Kr for the Ca2+-EDTA complex is 10.65 and the fraction of free EDTA in the Y- form, ay, is 0.041 at pH 9.00. What is K/, the conditional formation constant for Ca²+ at pH 9.00? What is the equivalence point volume, Ve, in milliliters? ml V = Ve= Calculate the concentration of Ca²+ at V = { v. [Ca2+1...
A 120.0 mL sample of 0.040 M Ca2+ is titrated with 0.040 M EDTA at pH...
A 120.0 mL sample of 0.040 M Ca2+ is titrated with 0.040 M EDTA at pH 9.00. The value of logKf for the Ca2+−EDTA complex is 10.65 and the fraction of free EDTA in the Y4− form, αY4−, is 0.041 at pH 9.00. What is Kf′, the conditional formation constant, for Ca2+ at pH 9.00? Kf′= What is the equivalence point volume, Ve, in milliliters? Ve= mL Calculate the concentration of Ca2+ at V=12Ve. [Ca2+]= M Calculate the concentration...
A 140.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH...
A 140.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log?f for the Ca2+−EDTA complex is 10.65 and the fraction of free EDTA in the Y4− form, ?Y4− , is 0.041 at pH 9.00. What is ?′f , the conditional formation constant, for Ca2+ at pH 9.00? ?′f= What is the equivalence point volume, ?e , in milliliters? ?e= mL Calculate the concentration of Ca2+ at ?=12?e . [Ca2+]= M...
A 100 mL sample of 0.060 M is titrated with 0.060 M EDTA at pH 9.00....
A 100 mL sample of 0.060 M is titrated with 0.060 M EDTA at pH 9.00. The value of Kf for the Ca^2+ -EDTA complex is 10.65 and the fraction of free EDTA in the Y^4- form, ay+ , is at pH 9.00. The Y4- was not given how am i suppose to solve this. What is Kf' , the conditional formation constant, for CA^2+ at pH 9.00? What is the equivalence point volume, Ve, in milliliters? Calculate the concentration...
Find the conditional formation constant for Ba(EDTA)2- at pH 9.00, where log Kf is 7.88 and...
Find the conditional formation constant for Ba(EDTA)2- at pH 9.00, where log Kf is 7.88 and Qyt is 0.041. K = 3.11 <106 Find the concentration of free Ba²+ in 0.060 M Na, [Ba(EDTA)] at pH 9.00. [Ba2+] = 1.93 x10-8
4. 50.0 mL of 0.00200 M Ca2 solution buffer at pH 10.0 is titrated with 0.00200 M EDTA. At equivalence point (i.e. 50.0 mL EDTA has been added), what is the equilibrium concentration of Ca2, [Ca2...
4. 50.0 mL of 0.00200 M Ca2 solution buffer at pH 10.0 is titrated with 0.00200 M EDTA. At equivalence point (i.e. 50.0 mL EDTA has been added), what is the equilibrium concentration of Ca2, [Ca2], and what is the pCa? The formation constant of CaY, Kaa 5.0 x 1010, and α4 of EDTA at pH 10.0 is 0.35
4. 50.0 mL of 0.00200 M Ca2 solution buffer at pH 10.0 is titrated with 0.00200 M EDTA. At equivalence point...
Page 243, Practical Question TABLE 12-1 Values of ye for EDTA at 25°C and -0.10 M...
Page 243, Practical Question TABLE 12-1 Values of ye for EDTA at 25°C and -0.10 M pH • Calculate (Ca2+] in 0.10 M CaY2- at pH 8.00, logKf(Ca2+ - EDTA) = 10.65. (answer: 2.3x10-5 M). 1.3 X 10-23 1.4 X 10-18 2.6 X 10-14 2.1 X 10-11 3.0 x 10 2.9 x 10-7 1.8 X 10- 3.8 X 10+ 4.2 x 10 Ca2+ + Y4- Cay2- 0.041 Conditional formation constant [MY-4) K = ayun Ky = m**][**] 0.30 0.81 0.98...
A solution containing 10.00 mL of 0.0500 M metal ion buffered to pH = 10.00 was...
A solution containing 10.00 mL of 0.0500 M metal ion buffered to pH = 10.00 was titrated with 0.0400 M EDTA. Answer the following questions and enter your results with numerical value only. Calculate the equivalence volume, Ve, in milliliters. Calculate the concentration (M) of free metal ion at V = 1/2 Ve. If the formation constant (Kf) is 1012.00. Calculate the value of the conditional formation constant Kf’ (=αY4- * Kf) and enter your result as scientific notation form....
A 120.0 mL sample of 0.040 M Ca2+ is titrated with 0.040 M EDTA at pH 9.00. The value of log Kr for the Ca2-EDTA complex is 10.65 and the fraction of free EDTA in the Y4 form, a, is 0.041 at pH 9.00 What is K, the conditional formation constant, for Ca2+ at pH 9.00? K What is the equivalence point volume, V, in milliliters? C Ve= mL Calculate the concentration of Ca2t at V Ca2+ М Calculate the...
A 150.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log Kr for the Ca2+-EDTA complex is 10.65 and the fraction of free EDTA in the Y- form, ay, is 0.041 at pH 9.00. What is K/, the conditional formation constant for Ca²+ at pH 9.00? What is the equivalence point volume, Ve, in milliliters? ml V = Ve= Calculate the concentration of Ca²+ at V = { v. [Ca2+1...
Find the conditional formation constant for Ba(EDTA)2- at pH 9.00, where log Kf is 7.88 and Qyt is 0.041. K = 3.11 <106 Find the concentration of free Ba²+ in 0.060 M Na, [Ba(EDTA)] at pH 9.00. [Ba2+] = 1.93 x10-8
4. 50.0 mL of 0.00200 M Ca2 solution buffer at pH 10.0 is titrated with 0.00200 M EDTA. At equivalence point (i.e. 50.0 mL EDTA has been added), what is the equilibrium concentration of Ca2, [Ca2], and what is the pCa? The formation constant of CaY, Kaa 5.0 x 1010, and α4 of EDTA at pH 10.0 is 0.35
4. 50.0 mL of 0.00200 M Ca2 solution buffer at pH 10.0 is titrated with 0.00200 M EDTA. At equivalence point...
Page 243, Practical Question TABLE 12-1 Values of ye for EDTA at 25°C and -0.10 M pH • Calculate (Ca2+] in 0.10 M CaY2- at pH 8.00, logKf(Ca2+ - EDTA) = 10.65. (answer: 2.3x10-5 M). 1.3 X 10-23 1.4 X 10-18 2.6 X 10-14 2.1 X 10-11 3.0 x 10 2.9 x 10-7 1.8 X 10- 3.8 X 10+ 4.2 x 10 Ca2+ + Y4- Cay2- 0.041 Conditional formation constant [MY-4) K = ayun Ky = m**][**] 0.30 0.81 0.98...
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