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The thrust propelling a rocket is given by the equ


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Answer #2

L = distance; M = mass; T = time; R = temperature

dimension(R) = L * (M * L/T^2) / (M * R) = [(L/T)^2]/R

dimension(RT) = (L/T)^2

dimension(sqrt(kRT)) = L/T (since k is dimensionless)

dimension(Nsqrt(kRT)) = L/T (since N is dimensionless)

dimension(F) = M*L/(T^2)

Therfore dimension of  \(\eta\) = [M*L/(T^2)]/(L/T) = (M/T) = mass/time

It represents the change in mass of the rocket due to burning of rocket fuel.

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Answer #3

It physically represents the mass flow rate.

Mass flow rate is the mass of a substance which passes through a given surface per unit of time.

Its unit is kiligram per second in SI i.e. kg/sec

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