QUESTION 50 A reaction is proceeding toward equilibrium. At a certain stage, the concentrations of reactants...

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Answer 1

Answer #1

Solution :

Question 50.

The answer will be the last option Q = 1

Explanation :

The relationship between the free energy of reaction at any moment in time ( Delta G) and the standard-state free energy of reaction ( Delta G^o) is given by :

Delta G = Delta G^o + RT ln Q

where R = universal gas constant ; T = temperature ; Q = Reaction Quotient ;

In the above equation, if we put Q = 1, we get ;

Delta G = Delta G^o

Question 49.

The answer will be the third option G^o = -2.90 kJ ; not forever ;

Explanation / Calculation :

The reaction is given as ;

C(diamond)C(graphite

We know,

$Delta G^{o} = Delta H^{o} - TDelta S^{o}$

where Delta G^o = standard free energy change ( to be calculated ) ; Delta H^o = standard enthalpy change = ( 0-1.895) = -1.895 kJ/mol ; T = Temperature = 298 K ; Delta S^o = entropy change = S^o(graphite) - S^o(diamond) = 5.740 - 2.337 = 3.403 J /molK

$Delta G^{o} = Delta H^{o} - TDelta S^{o}$

2983.403 1000 or. ▲Go-一1.895-298 ×

or, Δ o--2.909 kJ/mol~-2.91 kJ/mol

So, standard free energy change is -2.91 kJ/mol.

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Answer 2

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QUESTION 50 A reaction is proceeding toward equilibrium. At a certain stage, the concentrations of reactants...

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