Question

ASAP PLEASE

2. Interference, 35 points 2.1, 25 points. A single slit is illuminated wit th 500mm mm light, and the If the B resulting diffraction pattern is viewed on a sereen 3m awa distance betwen the irst dark fringe and the central bright fringe ofcl pattern is 15cm, what is the width of the slit? 2.2, 10 points. Another slit of the same width is added at a distance d forming a two-slit set up. The two slits are illuminated with 660nm light, and the resulting interference pattern is viewed on a screen 2m away. If the linear distance between the first dark fringe and the second dark fringe of the pattern is 25cm, what is d?

Answer 1

We know that for diffraction W . Y/L = lambda rightarrow W = lambda L/Y lambda = wave length L = Distance surface to slit Y = Distance between central Fringe to any other = 500 times 10^- 3 times 3/15 times 10^- 2 = 10 times 10^- 6 m w = 10 mu m width = 10 mu m For Interference d sin Theta = n lambda d Y/L = 1 lambda rightarrow d = lambda L/Y = 600 times 10^- 9 times 2/2.5 times 10^- 2 d = 4.8 mu m