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?I need 7,8,9 and 10. Please show work, thank you :)

For a circular merry-go-round, if the moment if in

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Answer #1

(7) m1= 8 KG

     m2 = 6 kg

Separation r = 0.5 m

Gravitational force F = Gm1m2/r 2

Where G = Gravitational constant = 6.67x10 -11 Nm 2/kg 2

Substitute values you get F = (6.67x10 -11)(6)(8) / 0.5 2

                                         = 1.28 x10 -8 N

(8) Moon has sufficient tangential speed

(9)Mass of satellite m = 10000 kg

Radius r = 1.2 x10 7 m

Mass of earth M = 6 x10 24 kg

Required gravitational field strength = GM/r 2

                                                   = (6.67x10 -11)(6 x10 24) /(1.2x10 7) 2

                                                   = 2.779 N/kg

Centripetal force = mv 2 / r

                        = GMm/r 2

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