Question

3. The glass plates in the figure are separated by a thin round filament. When the top plate is illuminated normally with a light of wavelength 570 nm, the filament lies directly below the fourth order bright fringe. What is the diameter of the filament? um
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Answer #1

3, for the given glass plates

for normal incidence on the top glass plate

the strand of the tube is directly under e4th order bright fringe

hence

path difference = 2d ( where d is diameter of the filament)

lambda = 570 nm

hence

2d = (2n - 1)*lambda/2

for fourth order maximum

n = 4

also, we use lambda/2 as the light has a phase reversal on the lower plate byt not when coming out of the upper plate

hence

2d = (7)lambda/2

d = 0.9975 um

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