3. (a) Find the partial derivatives (with respect to r and s) using the chain rule:[express...
a. Use the Chain Rule to find the indicated partial derivatives. z = x4 + x2y, x = s + 2t − u, y = stu2; ∂z ∂s ∂z ∂t ∂z ∂u when s = 1, t = 2, u = 3 b. Use the Chain Rule to find the indicated partial derivatives. w = xy + yz + zx, x = r cos(θ), y = r sin(θ), z = rθ; ∂w ∂r ∂w ∂θ when r = 8, θ = pi/2 c. Use the...
(b). Use the chain rule to find and so, where w = x2 + y2 + z2, x = st, y = scost, z = s sint when s= 1 and t=0.
Use the Chain Rule to find the indicated partial derivatives. и = = х2+ yz, x = pr cos e, y = pr sin , 2 = p+r ди др au ar au де when p = 2, r= 1, = 0 ди др au ar ди де
(b). Use the chain rule to find aw and as y = 8 cost, z = s sint when s= 1 and t=0 aw at where w = = 22 + y2 + z2, x = st,
#3 3. Using the change of coordinate formulas" find the partial derivatives of x, y, and z with respect to the cylindrical coordinates r, 0, z. 4 Using change of coordinate for 3. Using the change of coordinate formulas" find the partial derivatives of x, y, and z with respect to the cylindrical coordinates r, 0, z. 4 Using change of coordinate for
Find the first partial derivatives with respect to x, y, and z. W = x/yz4 + xy - 4yz
Du (b). Use the chain rule to find and y = scost, z = s sint when s = 1 and t=0 Ow at where w= = 22 + y2 + 22, r = st,
u=x+yz, Use the Chain Rule to find the indicated partial derivatives. x = pr cos , y = pr sin , 2-р+г ди диди др Әr" әө when p = 1, т. 3, = 0 ди др І ди ar ди Ә0
1. +0/1 points | Previous Answers TaalmanCalc1 12.5.021 Use the Chain Rule to find the indicated derivative. Express your answer as a function of a single variable d when z 12 sin x cos y, x -e, and y - 113 d 12e c 11s396?sin(^sin(113) 2. 0/1 points | Previous Answers TaalmanCalc1 12.5.022. Use the Chain Rule to find the indicated derivative. Express your answer as a function of a single variable dz when z = 7x10ey, x = sin...
Exercise 3. Chain rule (15 pts) Let f(x,y,z) = xy +z-5, x = r + 2s, y = 2r - sec(s),z=s af Then is: ar a. r - sec(s) b. sec(s) c. r+s+sec(s) d. 4r + 4s - sec(s) a. b. d.