Question

Review (MR).= -2.88 kN-m Submit Previous Answers Learning Goal: To determine the location and direction of a single equivalent force for a coplanar force system. The frame shown in (Figure 1) has dimensions H = 3.1 m and L = 0.9 m and is subjected to the forces P1 = 4.5 kN, P2 = 8.5 kN, and P3 = 11.5 KN. Force P3 is applied Ay = 0.4 m down from the top. ✓ Correct Part D Since the moment vector is out of the plane, it is perpendicular to the resultant force vector, which is in the plane. Therefore, the line of action of FR can be placed so that it produces the same moment about A as the original three forces produce. Where does this line of action intersect the line along AC? Express your answer to three significant figures with appropriate units. View Available Hint(s) y= 0.417 m Submit Previous Answers ✓ Correct Part E Where does the line of action intersect the line of CDE? Give the e-coordinate of the point. Express your answer to three significant figures with appropriate units. View Available Hint(s) Figure < 1 of 1 > ED LLC I= 0.183 m Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining < Return to Assignment Provide Feedback
Solve for E please

Answer 1

G. q kN 22.2 kN. 3.im. (Mens 2.88 kw.m. p Tral = 6.9 kW (fr), = 22.2 kN. = 2.88. 6.9 x 3.1 - 22.2 * .2 0.321m. THE CALCULATED VALVE SINCE 1S TO THE LEFT OF ORIGIN PART-E x=-0.321 m.