Question

Please Please Pease follow and meet all directions as advised in the problem in a (very clear handwriting of typing):

- For the MUST HAVE directions, you should have everything organized and labeled by its number in the same order(Rease divide each MUST HAVE with line so I know what are you referring to).

- This problem has 2 parts (A&B).

- Please write ALL equations before your answers.

- Summarize your answers as advised in the end and label it as (Summary).

- If you cannot follow these directions please do not answer.

Thank you a lot for your effort in educating me to solve such a problem.

Here is the problem:

In the sport of dock jumping, dogs run at full speed off the end of a dock that sits a few feet above a pool of water. The winning dog is the one that lands farthest from the end of the dock. If a dog runs at 8 m/s (a pretty typical speed for this event) straight off the end of a dock that is 1.0 m above the water, how far will the dog go before splashing down? Part (A) 1- Important Must Haves: (Follow them in order, and label them by # For A & B 1 2 Pictorial rep - motion diagram, instances identified, etc. 4 Four annotated graphs each with an equation to describe it. Mathematical work showing how you used these to solve problem. 5

Answer 1

ho = m , V = 4 - 8 pls , M - L so, R = UT we have to calculate T fint, vetticoad full ye Sy = Vyt + 19t h = 0+1972 - T- ºh. water now, acceleration VI alony U X-asis = 0 y-axis - og 104 R = Uy T = a velocity along X -axrs VE Mx + axt Ve=ux tiedoesn't chage with time) R = &v211 m ... R = 3.61m along y-axis y = Uy tayt 4 My = 1 now, uring Sx = ht + yat' Range maximum displacement Sy=R when t= Tl time of flight)

Parto T= y +Ju²tagn 1. (1 + ) AR- now, moximum distance R= x(+=+) = UxT wattt R = Sud ( 17 11 Criver; halm, initial velocities U= 8 mes, 0 = 30° Unzusino y = uuso -0 R= 4² sinouso/1+ (1+ agh ) 4 หp/ accelerations, - ax=0 una ay =g - 8² in 30 un 30 9.8 tindo com o (1+ / item yon + 2x9.81 g² rin? & velocity at - 64x63 l 489.8 U 69x VG IR = 7046 m time t y =ux , y = ly tgt - déplacement X = Uxt , Y = ht lyt + 12gt² - now, at te Il time of fight).. Y=o > O=-2gr + My Eth - T=-lly & rug?+ 2gh 9