Let us consider the upwards direction as positive and the downwards direction as negative.
Gravitational acceleration = g = -9.81 m/s2
Initial velocity of the dog = V0 = 8.5 m/s
The dog runs straight off the end of the dock that is the velocity of the dog is horizontal when it leaves the dock.
Initial horizontal velocity of the dog = Vx0 = 8.5 m/s
Initial vertical velocity of the dog = Vy0 = 0 m/s
Height of the dock = H= 0.61 m
Time before the dog hits the water = T
The displacement is downwards for the dog hence it is negative.
-H = Vy0T + gT2/2
-0.61 = (0)T + (-9.81)T2/2
T = 0.352 sec
There is no horizontal force acting on the dog hence the velocity of the dog in the horizontal direction remains constant.
Horizontal distance traveled by the dog = R
R = Vx0T
R = (8.5)(0.352)
R = 2.99 m
The dog will go 2.99 m before splashing in the water.
run at full speed off the end of pool of water. The winning dog is the...
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