Assymentric centres identified by two parameters
1.SP3Hyberidiszed
2.Four different functional groups attached around the carbon .
1) 2-methyl Butane
In the case of 2-methyl Butane this holds SP3 but does not have four different functional group around any one of the carbon.
2)2-Butene
In the case of 2-Butene this doe not holds SP3 for carbon 2and 3 because they are SP2and remaing carbons does not have four different functional group around any one of the carbon.
3)1-Dichloropropane
In the case of 1-Dichloropropane this holds SP3 but does not have four different functional group around any one of the carbon.
4)2-methyl-3-chloro hexane.(Assymentric Center)
In the case of 2-methyl-3-chloro hexane this holds SP3 carbon number 3 which has four functional group around it 1 hydrogen ,1chlorine,1 propane,1 methyl ethane , Hence carbon number 3 holds assymentric center
5)Cyclohexane
In the case of Cyclohexane this holds SP3 but does not have four different functional group around any one of the carbon.
ldentify the compound(s) with asymmetric centers Check all that apply. H3C CH3 CI CI CH2CH3 CI...
give the compound name = 0 CH3-CHY-CH2-CH2CH3 H3C-CH2-CH3 = H3C-CH2-CH2-CH2CH2-CH3 H2C=CH2 = H-C=C-CH3 = = H3C-CH2-CH2-OH = H2C=CH-CH2-CH2-CH3 = H3C-CH2-CH2-CH3 H3C-CH=CH-CH3 = = CH3-OH = CH3-CH2-OH = CH3-CH2-CH2-CH2-OH = CH3-CH-CH2-CH2-CH2-CH3 = 64 CH3-CH2-CH2-CH2-CH-OH = CH3-CH-CH2-CH, = H3C-CH2-C=0 H.C-CH2-CH2-CH2-C=0 HC-OH = H3C-CHCH2-f-OH H,C-CH2-COH
38) Name the following compound including the configuration of the asymmetric centers. CH3 Hai HHE I 0 i CH;
Explain why compound į has isolatable enantiomers, but compound ii does not: HI CH2CH3 -CH-N-CH3 Bro CH2CH2CH3 CH2CH3 CH2-N : CH2CH2CH3
Which of the following compounds has one or more asymmetric centers? Check all that apply. ロロロロロ
Name the compound below including any indicated stereochemistry. H3C. O CH3 CI H3C
Problem 47. 'rovide proper IUPAC names for each compound. CH2CH2CH3 CH2CHCH2CHCHCH; CH2CH3 CH3 48. Provide a name for the structure below. (IUPAC) CH3 419. Provide a name for the compound below. ĆUPAC) CH; CH,CECCHCH,CH2CH3 50. Provide the correct IUPAC name for the following compound. NOZ G CH 57. Give an acceptable name for the following substance. I UPAC HOCH,CH,OH S. Provide the IUPAC name for the structure below. H NO2 1. 53. Provide the IUPAC name for the following structure....
Which compound would have the highest boiling point? CH3CH2CH2CH2–OH CH3CH2–O–CH2CH3 CH3-O–CH2CH2CH3 он CH3CH2-CH-OH
Assign the R and S configuration at all asymmetric carbons. (The hydrogen atoms are not shown.) Incorrect Incorrect Incorrect Question 34 of 52 Map Assign the R and S configuration at all asymmetric carbons. (The hydrogen atoms are not shown) Assign the R and S configuration at all asymmetric carbons. (The hydrogen atoms are not shown.) CH3 CH3 CH2CH3 CH3 CH2CH3 CH3CH2 A rotated in space A ring flipped SR Incorrect. CH2CH3 CH3 CH3 CH2CH3 CH2CH3 diastereomer of B enantiomer...
Which of the reactions will yield the indicated compound as the major product? Check all that apply. CI (i) CI ♡ CI 1. HNO3, H2SO4 2. HN(CH3)2 NO2 CI (ii) 1. HNO3, H2SO4 2. HN(CH3)2 NO2 CI CI (iii) OCH3 OCH3 1. HNO3, H2SO4 2. HN(CH3)2 O2N CI (iv) OCH3 1. NaN(CH3)2, HN(CH3)2 OCHZ 2. Br2 Br H2C H2C CI (v) H3C AICI: H3C CH3 CH3 (vi) H2N 1) HNO3, H2SO4 HN 2) NaOH, H2O NO2
Answer: Enantiomers 31. a. Comparing two molecules: The Same: all centers match (R versus S, or by alignment of the Fischer Projection) Enantiomers: all centers are completely the opposite (R versus Sor by not being able to completely align the Fischer Projection) Diastereomers: some centers completely match while other centers do not. H Br NH Br CH2CH3 HO CH3 H CE *CH3 F OH d CH2CH 3 NH 2 H Br ch H cl H3C OH нзу Br H3C CH...