Question

Electric Circuits

Find the charge in each capacitor shown in Figure 4.

Thanks in advance.

4. Find the charge in each capacitor as shown on Fiq.4 2 Fig,4

Answer 1

the net capacitance C_net = series(1 + 2) and parallel (3)

1/C_series = 1/C₁ + 1/C₂

C_{parallel =} C₁ +C₂

so the net capacitance of (1 and 2) = 0.66 micro F

and hence total capacitance of the system = 3 + 0.666 = 3.666 micro F

when capacitors are in series, the charge remains same across them . so the capacitance will be same across 1 and 2 micro farad capcitors, and its value = Q= CV = 0.666 * 5 = 3.33 Coloumb

and the charge across 3 micro F = 3*5 = 15 coloumb