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A ball is launched into the air from below a cliff, such that after t seconds its height above the cliff top is h metres, and

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Everything I have explained in a neat and clean way with proper explanation, for all that you need to see just this attachment, hope you will love the solution/explanation like this, Thank you :) and have a good day ahead !!!Fren equaton is --49t+19-6t 2. 36 -4.9(t2-4t 2t0-2 th path ball LaunCed -vleddy and at maximum hayht vel -o 9.8t +19.6 olt h9

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