p1= x1/n1 = 368/541= 0.6802
p2= x2/n2 = 421/593 = 0.7099
So, 90% CI for the difference in the population proportion is given as:
p1- p2 +- z 0.05*√p1*(1-p1)/n1 + p2*(1-p2)/n2
= -0.1017 +- 1.645*0.0281
= (-0.148, -0.056)
We are 90% confident that the true difference between p1 and p2 lies in the above interval.
\ In Problems 7–10, construct a confidence interval for p - P2 (it the given level...
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