1. In the H NMR of benzaldehyde, which proton is responsible for the resonance at 10.0 ppm? In the aromatic area there are three sets of multiplets at 7.87, 7.61 and 7.51 that integrte for 2:1:2 protons respectively. Which protons are responsible for these multiplets?
In the C NMR of benzaldehyde, which carbon is responsible for the resonance at 192 ppm?
Homework Answers
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1. In the H NMR of benzaldehyde, which proton is responsible for
the resonance at 10.0...
1.Which protons in methyl salicylate are resonsible for the resonance at 10.7 ppm? Which are responsible...
1.Which protons in methyl salicylate are resonsible for the
resonance at 10.7 ppm? Which are responsible forthe resonance at
3.9 ppm?
2. Which carbon in methyl salicylate is respocsible for the
resonance at 170.6 ppm? Which is responsible for the resonance at
52.2 ppm?
3. In the aromatic area of the proton NMR of methyl salicylate
there is a doublet at 7.81 ppm. Which aromatic proton in the
structure is responsile for this resonance?
4. What is the major new...
In the aromatic area of the proton NMR of methyl salicylate there is a doublet at 7.81 ppm. Which aromatic proton in the structure is responsible for this resonance?
In the aromatic area of the proton NMR of methyl salicylate there is a doublet at 7.81 ppm. Which aromatic proton in the structure is responsible for this resonance?
2. Below are the aromatic regions for the proton NMR spectra for four isomers of dimethoxybenzaldehyde....
2. Below are the aromatic regions for the proton NMR spectra for four isomers of dimethoxybenzaldehyde. These isomers are: 2,4-dimethoxybenzaldehyde, 2,5-dimethoxybenzaldehyde, 2,6-dimethoxybenzaldehyde, and 3,4 dimethoxybenzaldehyde. Draw the structure responsible for each spectrum in the box to the right of the spectra. To help in solving this problem, remember that aldehyde groups are electron withdrawing through resonance. Therefore, nearby protons would be deshielded. On the other hand, methoxy groups are electron donating through resonance. Therefore, nearby protons would be shielded. (10...
9. H NMR analysis - 2 points total a. Assign only the aldehyde proton (Ha) in...
9. H NMR analysis - 2 points total a. Assign only the aldehyde proton (Ha) in the H NMR spectrum of 9-anthraldehyde (CDC13, 60 MHz). The aromatic protons are overlapping (9-7.5 ppm) and it is challenging to individually assign them all (0.25 point) Havo Aromatic protons 11.5297 POCO 6- -8.9060 -8.6782 -8.1397 -7002 2.001.02 6.03 90 115 11.0 105 10 0 95 45 40 35 3.0 85 80 751 7065 60 55 50 Chemical Shift (ppm)
QUESTIONS HO — а Hab The 'H-NMR of the product shows two doublets in the aromatic...
QUESTIONS HO — а Hab The 'H-NMR of the product shows two doublets in the aromatic region (at ~7.8 ppm and 6.7 ppm with equal relative integration) H. and a very broad signal (the signal is almost flat from ~5.0 ppm to ~6.5 ppm and may actually extend into the doublet at ~ 6.7 ppm) which may indicate a "combination" of the amine and acid peaks. W h o o Hd The amine group can be considered to be electron...
1. [2 pts] Identify which signal on the proton NMR is produced by which proton or...
1. [2 pts] Identify which signal on the proton NMR is produced by which proton or set of protons in the molecule shown. Assign protons a-e to the signals. 3 2 PPM 0 2. [2.5 pts] Evaluate the following proton NMR and determine which compound produced the NMR. Circle the answer and indicate one reason why each of the other answers must be wrong. Be specific in your reasons PPM Br Br Br Br Br CH3
IR Spectra help, question up top Use IR. proton NMR and MS data to deduce the...
IR Spectra help, question up top
Use IR. proton NMR and MS data to deduce the correct structure Draw the structure and dide it. Indicate on the IR, NMR and MS spectra the information you got from each to deduce the structure. Problem 20 IR Spectrum 4000 3000 2000 1800 12000 00 8 Mass Spectrum 8 8 No significant UV absorption above 220 nm 8 8 CgH NO 240 280 40 80 120 180 200 13C NMR Spectrum (1000 MHE....
For the 1H NMR of 3-Acetyl-benzaldehyde, label which peak belongs to which proton of the molecule....
For the 1H NMR of 3-Acetyl-benzaldehyde, label which peak
belongs to which proton of the molecule. (Peak 3 is a quartet;
Peaks 1,2, and 4 are singlet)
'H NMR Common Name: IUPAC Name: CAS No.: Zoom Out Solvent: BP: MP: 1.00 0.90 0.80 0.70 0.60 0.50 0.40 0.30 w 0.20 0.10 0.00! 10.0 7.0 4.0 2.0 1.0 0.0 -0.5 6.0 Height 8.0 No. 4 No 1 3.0 Height 9.0 Height 73.744 66.931 126.98 Height 199.59 5.0 No. 10 11 Height...
STRUCTURE DETERMINATION PROBLEMS USING IR AND PROTON NMR SPECTROSCOPY Determine the structure of the six compounds...
STRUCTURE DETERMINATION PROBLEMS USING IR AND PROTON NMR
SPECTROSCOPY
Determine the structure of the six compounds whose IR and PMR
spectra are provided on the attached sheets, given the following
comments about the provided information and spectra.
PMR Spectra: The PMR spectrum of each compound is provided,
along with peak areas. The peak areas are given as the simples
whole number ratio of protons and are indicated (for exmpale, 4H).
Your final structure must be consistent with the chemical shift...
Deduce the following structure of the compound given their IR, H1 NMR, 13C NMR spectra, and...
Deduce the following structure of the compound given their IR, H1
NMR, 13C NMR spectra, and assign IR functional group absorptions
and assign the structure's protons and carbons to their respective
spectral resonances.
Compound 4 Da- U6)+20 IR Spectrum Oquid fim) 1760 800 1200 2000 1600 3000 4000 v (cm) Mass Spectrum 100 43 No significant UV absorption above 220 nm M146 (1% ) 87 20 CH1004 280 40 80 120 m/e 160 200 240 13C NMR Spectrum (1000 MHz,...
1.Which protons in methyl salicylate are resonsible for the
resonance at 10.7 ppm? Which are responsible forthe resonance at
3.9 ppm?
2. Which carbon in methyl salicylate is respocsible for the
resonance at 170.6 ppm? Which is responsible for the resonance at
52.2 ppm?
3. In the aromatic area of the proton NMR of methyl salicylate
there is a doublet at 7.81 ppm. Which aromatic proton in the
structure is responsile for this resonance?
4. What is the major new...
2. Below are the aromatic regions for the proton NMR spectra for four isomers of dimethoxybenzaldehyde. These isomers are: 2,4-dimethoxybenzaldehyde, 2,5-dimethoxybenzaldehyde, 2,6-dimethoxybenzaldehyde, and 3,4 dimethoxybenzaldehyde. Draw the structure responsible for each spectrum in the box to the right of the spectra. To help in solving this problem, remember that aldehyde groups are electron withdrawing through resonance. Therefore, nearby protons would be deshielded. On the other hand, methoxy groups are electron donating through resonance. Therefore, nearby protons would be shielded. (10...
9. H NMR analysis - 2 points total a. Assign only the aldehyde proton (Ha) in the H NMR spectrum of 9-anthraldehyde (CDC13, 60 MHz). The aromatic protons are overlapping (9-7.5 ppm) and it is challenging to individually assign them all (0.25 point) Havo Aromatic protons 11.5297 POCO 6- -8.9060 -8.6782 -8.1397 -7002 2.001.02 6.03 90 115 11.0 105 10 0 95 45 40 35 3.0 85 80 751 7065 60 55 50 Chemical Shift (ppm)
QUESTIONS HO — а Hab The 'H-NMR of the product shows two doublets in the aromatic region (at ~7.8 ppm and 6.7 ppm with equal relative integration) H. and a very broad signal (the signal is almost flat from ~5.0 ppm to ~6.5 ppm and may actually extend into the doublet at ~ 6.7 ppm) which may indicate a "combination" of the amine and acid peaks. W h o o Hd The amine group can be considered to be electron...
1. [2 pts] Identify which signal on the proton NMR is produced by which proton or set of protons in the molecule shown. Assign protons a-e to the signals. 3 2 PPM 0 2. [2.5 pts] Evaluate the following proton NMR and determine which compound produced the NMR. Circle the answer and indicate one reason why each of the other answers must be wrong. Be specific in your reasons PPM Br Br Br Br Br CH3
IR Spectra help, question up top
Use IR. proton NMR and MS data to deduce the correct structure Draw the structure and dide it. Indicate on the IR, NMR and MS spectra the information you got from each to deduce the structure. Problem 20 IR Spectrum 4000 3000 2000 1800 12000 00 8 Mass Spectrum 8 8 No significant UV absorption above 220 nm 8 8 CgH NO 240 280 40 80 120 180 200 13C NMR Spectrum (1000 MHE....
For the 1H NMR of 3-Acetyl-benzaldehyde, label which peak
belongs to which proton of the molecule. (Peak 3 is a quartet;
Peaks 1,2, and 4 are singlet)
'H NMR Common Name: IUPAC Name: CAS No.: Zoom Out Solvent: BP: MP: 1.00 0.90 0.80 0.70 0.60 0.50 0.40 0.30 w 0.20 0.10 0.00! 10.0 7.0 4.0 2.0 1.0 0.0 -0.5 6.0 Height 8.0 No. 4 No 1 3.0 Height 9.0 Height 73.744 66.931 126.98 Height 199.59 5.0 No. 10 11 Height...
STRUCTURE DETERMINATION PROBLEMS USING IR AND PROTON NMR
SPECTROSCOPY
Determine the structure of the six compounds whose IR and PMR
spectra are provided on the attached sheets, given the following
comments about the provided information and spectra.
PMR Spectra: The PMR spectrum of each compound is provided,
along with peak areas. The peak areas are given as the simples
whole number ratio of protons and are indicated (for exmpale, 4H).
Your final structure must be consistent with the chemical shift...
Deduce the following structure of the compound given their IR, H1
NMR, 13C NMR spectra, and assign IR functional group absorptions
and assign the structure's protons and carbons to their respective
spectral resonances.
Compound 4 Da- U6)+20 IR Spectrum Oquid fim) 1760 800 1200 2000 1600 3000 4000 v (cm) Mass Spectrum 100 43 No significant UV absorption above 220 nm M146 (1% ) 87 20 CH1004 280 40 80 120 m/e 160 200 240 13C NMR Spectrum (1000 MHz,...
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