CH3COOH + NaOH ---------> CH3COONa + H2O
millimoles of CH3COOH = 10.0 x 0.10 = 1.0
millimoles of NaOH added = 37.5 x 0.100 = 3.75
3.75 - 1.0 = 2.75 millimoles NaOH left
[NaOH] = 2.75 / 47.5 = 0.056 M
as NaOH is strong base
[NaOH] = [OH-] = 0.056 M
pOH = - log OH-]
pOH = - log [0.056]
pOH = 1.25
pH = 14 - 1.25
pH = 12.75
Due Sunday, Nov 4, 11:59pm EST 9 Calculate pH During Acid Base Titration CONTENT FEEDBACK Question...
10:08 9 - UEH Assignment Empirical and Molecula... Due Monday, Nov 25, 11:59pm EST - Calculate the percent composition of a compound given Questionents A 17.10 g compound is made up of 5.900 g N and 11.20 g C. What is the percent composition of nitrogen in this compound? • Your answer should have four significant figures. Provide your answer below: % MORE INSTRUCTION SUBMIT Content attribution
Calculate pH during acid base titration Question When titrating a strong acid with a strong base, after the equivalence point is reached, the pH will be determined exclusively by: Select the correct answer below: O hydronium concentration O hydroxide concentration O conjugate base concentration O conjugate acid concentration FEEDBACK MORE INSTRUCTION SUBMIT Content attribution
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CollegeBoard AP Classroom Unit 8 Progress Check: MCQ - - --0-0--0-0-0-0-0--- - - - - - - - - - Question 12 CH,CH,COOH(aq) + H2O(1) = H,0*(aq) + CH,CH,COO() K. -1.4 x 10-st 25°C CH, CH-000 (aq) + H2O(1) = CH.CH,COOH(aq) + OH(aq) K - 7.4 x 10-st 25°C The acid equilibrium for CH,CH,COOH and the base equilibrium for CH,CH,COO" are represented above. One liter of a buffer solution with pH 4.85 is made by mixing 0.100 M CH,CH,COOH and...
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Ch 17 Ee 12 Weak Acid/Strong Base: Example 8: An acid-base titration experiment begins with 20.0 ml of 0.200 M HF in the flask and 0.160 M NaOH in the burer. Ka for HF-6.3 x 10-4. Draw the expected titration graph where pH is the y axis and ml of NaOH added is the x axis, Sketch and label the titration curve including WA or WB, SA or SB, salt, equivalence pt. pH at equiv pt <-, or > 7....
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Itsuultes Lx Give Up? Feedback Resume < Question 25 of 25 > Attempt 4 - Calculate the pH of the resulting solution if 30.0 mL of 0.300 M HCl(aq) is added to 40.0 mL of 0.300 M NaOH(aq). pH = 12.63 Calculate the pH of the resulting solution if 30.0 mL of 0.300 M HCl(aq) is added to 20.0 mL of 0.400 M NaOH(aq). pH = 12.16 Question Source: MRG-General Chemistry Publisher: University Science Books