Question

CollegeBoard AP Classroom Unit 8 Progress Check: MCQ - - --0-0--0-0-0-0-0--- - - - - - - - - - Question 12 CH,CH,COOH(aq) + H2O(1) = H,0*(aq) + CH,CH,COO() K. -1.4 x 10-st 25°C CH, CH-000 (aq) + H2O(1) = CH.CH,COOH(aq) + OH(aq) K - 7.4 x 10-st 25°C The acid equilibrium for CH,CH,COOH and the base equilibrium for CH,CH,COO" are represented above. One liter of a buffer solution with pH 4.85 is made by mixing 0.100 M CH,CH,COOH and 0.100 M NACH,CH,000. 10.0 mL of 0.500 M NaOH is added to the buffer, which of the following is most likely the resulting pH, and why? (A) The pH will be much less than Rs because the buffer will respond to the addition of NaOH by producing more CH.CH,COOH The pit will be much greater than 485 because there is a large increase in the concentration of the weak b e, CH CH.000 The pH will be slightly less than 485, because the addition of NaOH reduces the stolonization of H20 The pll will be greater than 48, because some CH,CH,COOH will react with the added bases, resulting in a slight decres (HO

Answer 1

Therefore the pH will be slightly greater than 4.85 as the acid react with the base added forming the salt and decreasing the concentration of H​​​​​3​​​​​O+ slightly.