Design a DFA that accepts the set of all strings with 3 consecutive zeros at anywhere?
Design a DFA that accepts the set of all strings with 3 consecutive zeros at anywhere?
For ∑ = {a, b}, construct a dfa that accepts the set consisting of all strings with exactly one a
For ∑ = {a, b}, construct a dfa that accepts the set consisting of all strings with at least one b and exactly two a’s
Design a DFA with 2 states that accepts the language of all binary numbers that are divisible by 3. Demonstrate it with a two-state DFA and a proof that the accepted language is precisely binary strings representing numbers divisible by 3. Otherwise, prove that such a two-state DFA is impossible.
Draw a DFA which accepts the following language over the alphabet of {0,1}: the set of all strings such that there are no consecutive 0s, and the number of 1s is divisible by 5. Your DFA must handle all intput strings in {0,1}*. Here is a way to approach the problem: First focus only building the DFA which accepts the language: As you build your DFA, label your states with an explanation of what the state actually represents in terms...
Build a DFA that accepts the described language: The set of strings over {a, b} in which every a is either immediately preceded or immediately followed by b, for example, baab, aba, and b.
Draw a DFA that accepts all binary strings of length 4 modulo 7.
Give a DFA over {a,b} that accepts all strings containing a total of exactly 4 'a's (and any number of 'b's). For each state in your automaton, give a brief description of the strings associated with that state.
1.A: Let Sigma be {a,b}. Draw a DFA that will accept the set of all strings x in which the last letter of x occurs exactly twice in a row. That is, this DFA should accept bbabbbaa (because there are two a's at the end), and aaabb (two b's), but should not accept aaa (3 a's in a row, and 3 is not exactly 2), nor single letter words such as 'b', nor baba, etc.
Part B - Automata Construction Draw a DFA which accepts the following language over the alphabet of {0,1}: the set of all strings such that the number of 0s is divisible by 2 and the number of 1s is divisible by 5. Your DFA must handle all intput strings in {0,1}*. Here is a methodical way to do this: Figure out all the final states and label each with the shortest string it accepts, work backwards from these states to...
Automata Question. Over the alphabet Σ = {0, 1}: 1) Give a DFA, M1, that accepts a Language L1 = {all strings that contain 00} 2) Give a DFA, M2, that accepts a Language L2 = {all strings that end with 01} 3) Give acceptor for L1 intersection L2 4) Give acceptor for L1 - L2