Question

Ammonia reacts with oxygen according to the equation: ANH3(g) +502(g) → 4NO(g) + 6H2O(g) AH.. = --906 kJ Calculate the heat (in kJ) associated with the complete reaction of 305 g of NH3 Express your answer with the appropriate units.

Answer 1

# Given 4NH₃ (G) + 50 (9) 400 (G) + 6H₂0G). A Hoon = - 906 kJ from the above balanced chemical Dreaction , it is clear that -906 kJ of energy is associated with 4 moles of But we have 305 g of NH₃ Therefore firstly, we calculate the number of moles of NH₃ present 1305 g of NH₃. in Number of moles y NH = SOS Ginen Mass of NH₃ molar mass of NH₃- = 3059 17.0304 mol = 17.9085197 mol This means we have to the heat associated with mole of NH₃, calculate 17.9085197

• Heat asociated with 4 mole of NH₃ = -906 KI I Heart associated with I mole of NH₃ = - yob ka • Heat associated with 17.9085197 mole of NH3 = -906 17.985 197 KJ - 4056.27 97120 K I
Therefore,

4056.2797120 KJ of Heat is associated with the complete reaction of 305 g Of NH_3.

Thank You.