Question

9. (2pts) Molecule A as a liquid, forms hydrogen bonds. Molecule B is non-polar. Which of these mol ecular liquids will have the higher boiling point, Molecule A or Molecule B? (Circle one) Why? Which of these molecular liquids will have the lower vapor pressure, Molecule A or Molecule B? (Circle one) Why? 10. (2pts) Which anion has the smaller radius, Br or I? (Circle one) Why? Which cation has the larger radius, Na* or Mg Why? (Circle one) 11. (1.5pts) Circle your answers to a and b below. a. Which type of bond, sigma or pi, allows free rotation? b Which type of bond, sigma or pi, has electron density above and below the intermolecular axis? C. Can there be a pi bond without a sigma bond?

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Answer #1

9.Molecule A will have higher boiling point.Due to H bonding the the molecular forces of attraction between molecule A will be higher and thus will require greater amount of energy to convert it from liquid to gas.

Molecule A will have lower vapour pressure as it has strong force of attraction in liquid state(hydrogen bonding).

10. Br - will have smaller radii than I -

Br- has outermost electronic configuration of 4s24p6 , I - has outermost electronic configuration of 5s25p6 .

11. a)Sigm bond allows rotation of bonds

b) Pi bond has electron density above and below the intermolecular axis

C) no

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