Question

What would be the output of the following code? def get_letter_index(letter, string): returns the index of letter in string, OR if letter is not found in string, prints that information instead. If the letter occurs multiple times, this returns only the first index where the letter is found. Index where the letter is found for i in range(len(string)): if string[i] == letter: return i #if execution reaches this point, we must not have found the letter print(letter, "not found in", string) my_string = "alpha" p_index = get_letter_index("p", my_string) print(my_string[p_index])

Answer 1

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Answer : p

there fore the output of following code is "p".

Explanation :

Instalize my_string with "alpha"
after we call the method get_letter_index() with arguments letter "p" and string my_str

Inside method :
   for loop itterates from i =0 to length of the given string
   check if i =0:
       string[0] == "p" false because string[0] is "a" so loop itterate
   check if i =1 :
       string[1] == "p" false because string[1] is "l" so loop itterate
   check if i =2 :
       string[2] == "p" true because string[2] is "p" so loop returns i i.e(i=2)

we assign that value to p_index i.e p_index = 2

finally we print the my_string[p_index] i.e the value of my_string[2] is "p"