Question

Problem 5: segment ing filamentary triangle joins points Ate.a.2, HIDA.A amd CaAS) The a current of 1 A in the ase direction. There is a present magnetie ield B-0.4ax-0.2ay +0.6az T. Find: (a) the force on segment BCs about an origin at A. an) × ( n,, a, (a) FA = =( )( ax ay az N (b) Rgc1/4* CR CA ay TA ay clear all; clc PAs [6 8); B=[0.4-0. 4); PC= [2 4 1-1; PA [6 2 21 PB- [1 2); PB= [10 8 2 %a) RBC= FA= %b) RAB= RCA= &Origin at A-6 2 2] 2 RBC-1/4* (RCA-RAB) TA=

Answer 1

r) -H bo と ах. ·)デ Ν.M ナチ"dax