calculate the molarity of each of the following solutions
1- 0.54 mole of BaCl2 in 100.0mL of solution
2- 0.230 mole of Na2CO3 in 200 mL
3- 0.325 mole of C6H12O6 in 250.0 mL
4- 1.384 mole of KNO3 in 250.0mL
Molarity has the equation:
M = mol of solute / Liter of solution
1)
M = mol/L = 0.54 / 100 ml = 0.54 / 0.1 L = 5.4 mol per liter
2)
M = mol/L = 0.23 / 200 ml = 0.23 / 0.2 L = 1.15 mol per liter
3)
M = mol/L = 0.325 / 250 ml = 0.325/ 0.25 L = 1.3 mol per liter
4)
M = mol/L = 1.384 / 250 ml = 1.384 / 0.25 L = 5.536 mol per liter
NOTE that mol per liter is equivalent to "Molar"
calculate the molarity of each of the following solutions 1- 0.54 mole of BaCl2 in 100.0mL...
Calculate the molarity of each of the following solutions. 1st attempt Part 1 (1 point) 0.650 mol of BaCl2 in 100.0 mL of solution M Part 2 (1 point) 0.190 mol of Na2CO3 in 200.0 mL of solution M Part 3 (1 point) 6.00 mol of CoH1206 in 250.0 mL of solution M Part 4 (1 point) 1.45 mol of KNO3 in 250.0 mL of solution M
calculate the molarity of each of the following solutions: 1. 4.45 mol of LiCl in 2.20 L solution 2. 28.93 g C6H12O6 in 1.11 L of solution 3. 34.3 mg NaCl in 119.0 mL of solution
Find the molarity of the following solutions: Molarity = mole/Liters 1 liter - 1000 ml 1) 2.5 moles of NaCl is dissolved to make 0.050 liters of solution 2) 3.0 moles of AgCl is dissolved in enough water to make a 2.0 liter solution 3) 4.2 moles of lithium fluoride are dissolved in 2 liters of solution. 4) 18 grams of hydrochloric acid, HCl is dissolved to make 1 liter of solution.
plesse help!! Calculate the molarity of an aqueous solution containing 1.80 mole potassium chloride in a 800. mL solution Calculate molarity of an aqueous solution containing 5.20 g ammonium sulfate in a 250.0 mL solution. Calculate the moles and the mass of solute present in 200. mL of 0.400 M sodium nitrate solution. How many mL of a 0.620 M solution will contain 0.250 moles of calcium chloride?
Calculate the molarity of the following solutions. A.) 0.800 mole glucose in 0.450 L of a glucose solution Express your answer with the appropriate units. B.) 83.5 g of HCl in 2.00 L of a HCl solution Express your answer with the appropriate units. C.) 36.5 g of NaOH in 350. mL of a NaOH solution Express your answer with the appropriate units.
Calculate the molarity of each of the following ions. 4th attempt Part 1 (1 point) 0.933 g Nat in 130.0 mL of a NaCl solution. Part 2 (1 point) 0.760 g of Cl in a 130.0 mL of a NaCl solution. Part 3 (1 point) 0.400 g of SO42- in 130.0 mL of Na2SO4 solution. Part 4 (1 point) 0.230 g of Ca2+ in 130.0 mL of CaCl2 solution.
QUESTION 1 Calculate the molarity of each of the following: a. 0.500 mole of glucose in 0.200 L of a glucose solution b. 73.0 g of HCl in 2.00 L of a HCl solutionQUESTION 2 Indicate whether aqueous solutions of each of the following solutes contain only ions, only molecules, or mostly molecules with a few ions. a NH4CI, a strong electrolyte b. ethanol, C2H5OH, a non electrolyte c. HCN, hydrocyanic acid, a weak electrolyte QUESTION 3 Describe the formation of an aquesous Kl solution when solid Kl dissolves...
Calculate the molarity of each of the following: 1st attempt Part 1 (1 point) 66.0 g LiCl in 250.0 mL of solution Part 2 (1 point) 30.0 g NiSO4 in 200.0 mL of solution Part 3 (1 point) 55.0g KCN in 500,0 mL of solution
Calculate the molarity of the following solutions: a A sample of solid KBr weighing 18.0 g is put in enough distilled water to give 350 ml. of solution. Molarity = M D A 17.1-g sample of solid Naz 804 is dissolved in enough water to give 700 mL of solution Molarity = M C A 40.0 mL sample of solution is evaporated to dryness and leaves 0.54 g of solid residue that is identified as LigSO4 Molarity = Submit Answer...
CH08 Required HW 11/ 02 Question (1 point) Calculate the molarity of each of the following: 1st attempt Part 1 (0.3 point) 69.0 g LiCl in 250.0 mL of solution Part 2 (0.3 point) 26.0 g NiSO4 in 200.0 mL of solution 1 OF 18 QUESTIONS COMPLETED Part 1 (0.3 point) 69.0 g LiCl in 250.0 mL of solution Part 2 (0.3 point) 26.0 g NISO4 in 200.0 mL of solution Part 3 (0.3 point) 49.5 g KCN in 500.0...