3 mol of helium gas are held in a 1-L container at 20◦C (1000 L = 1 m3).1. Assuming the helium acts like an ideal gas under these conditions, what is the pressurepof the gas in kPa? (3 pts)2. Recalculate the pressure of the gas using the Van der Waals equation. What is theratio of this pressure to that from part 1? The Van der Waals constants for helium area= 3.46×10−3Jm2/mol2andb= 2.38×10−5m3/mol. (4 pts)
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3 mol of helium gas are held in a 1-L container at 20◦C (1000 L =...
A 1.55-mol sample of nitrogen gas is maintained in a 0.730-L container at 292 K. Calculate the pressure of the gas using both the ideal gas law and the van der Waals equation (van der Waals constants for N2 are a = 1.39 L2atm/mol2 and b = 3.91×10-2 L/mol). Pideal gas equation = ______ atm Pvan der Waals =_____ atm
Hint: % difference = 100×(P ideal - Pvan der Waals) / P idealAccording to the ideal gas law, a 9.843 mol sample of argon gas in a 0.8425 L container at 502.0 K should exert a pressure of 481.3 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Ar gas, a =1.345L2 atm/mol2 and b = 3.219×10-2 L/mol.
A 9.083 mol sample of methane gas is maintained in a 0.8377 L container at 304.9 K. What is the pressure in atm calculated using the van der Waals' equation for CH4 gas under these conditions? For CH4, a = 2.253 L^2atm/mol^2 and b = 4.278 x 10^-2 L/mol.
A 10.13 mol sample of krypton gas is maintained in a 0.7517 L container at 297.2 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L2atm/mol2 and b = 3.978×10-2 L/mol.
A 9.262 mol sample of xenon gas is maintained in a 0.8496 L container at 299.3 K. What is the pressure in atm calculated using the van der Waals' equation for Xe gas under these conditions? For Xe, a = 4.194 L2atm/mol2 and b = 5.105×10-2 L/mol.
A 9.386 mol sample of methane gas is maintained in a 0.7854 L container at 302.4 K. What is the pressure in atm calculated using the van der Waals' equation for CH4 gas under these conditions? For CH4, a = 2.253 L2atm/mol2 and b = 4.278×10-2 L/mol.
A 9.450 mol sample of krypton gas is maintained in a 0.8100 L container at 300.1 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L2atm/mol2 and b = 3.978×10-2 L/mol. atm
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L’atm/mol and b = 3.978x10-2 L/mol. atm
If 1.00 mol of argon is placed in a 0.500-L container at 30.0 ∘C , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2⋅atm)/mol2 and b=0.03219L/mol.
A 10.74 mol sample of oxygen gas is maintained in a 0.8354 L container at 296.1 K. What is the pressure in atm calculated using the van der Waals' equation for O2 gas under these conditions? For 02, a = 1.360 Latm/mo12 and b = 3.183x10-2 L/mol. atm