If 1.00 mol of argon is placed in a 0.500-L container at 30.0 ∘C , what...

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If 1.00 mol of argon is placed in a 0.500-L container at 30.0 ∘C , what...

If 1.00 mol of argon is placed in a 0.500-L container at 30.0 ∘C , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2⋅atm)/mol2 and b=0.03219L/mol.

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Answer 1

Answer #1

Cv) veurne 0.500 L R: 0,0821 Lahn PÏ = 49.15 alin. Real Gos 2 3 l) * [o.cvocu)-lo)xo.08219 {k = 53.267 an.-538 ah 49.75-41.29

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