Question

body fat is r actual weight (on dry land) water... T'his allows you to calculate their volume, which in turn can be used to find their ) with their weight as measured by a scale while they are suspended under specific gravity; which yields their percent body fat: 495 specific gravity % body fat-( ) 450 On dry land, an athlete weighs 70.2 kg The same athlete, when submerged in a swimming pool and hanging from a scale has an "apparent (underwater) weight" of 3.4 kg. a) (50 pts) Calculate the volume of the athlete. b) (40 pts) Assume their lungs hold l .3× 10 3 m3 of air, so their true volume is the answer from part a, minus 1.3x10 3 m3. Calculate their specific gravity. (10 pts) Using the equation above, calculate their percent body fat. c) Hints: The density of water is 1.00x103 kg/m3. . g is 9.8 m/s2 □ Grade This Problem vol.

Answer 1