Homework Answers
Molecular weight of Na2S2O3= 158
moles of Na2S2O3 in 20.4 gms =20.4/158=0.129 moles
molarity = moles of Na2S2O3 in liter of solution =0.129/0.25= 0.516
moles of Na2S2O3 in 25 ml of sample taken= 0.516*25/1000=0.0129
Molarity of final solution = 0.0129/0.5 =0.0258 Mol/L
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