given
f = 16.22mm
focal length of eye piece = 9.5mm
length of barrel set=29cm
angle = 1.43 m rad
image distance = 29cm
m =[ L / fo ] * [ 1 +D / fe]
Where D is the distance of distinct vision = 270 mm
Using the given values
m = 270 mm / 16.22 mm { 1 + 270 mm / 9.5 mm}
m = 489.74= size of the image / size of the object.
489.74=( 29 cm * 1.43 x 10^-3 ) / ( size of the object.)
size of the object = 29 cm x 1.43 x 10^-3 / 489.74=0.0846*10^-3 cm
=84.6μ m
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