Question

step by step process with chart if needed

inpelu,Faisal (1) Math 111 CMD Test 5 Fall 2019 Pre Wed 20 November 27, 2019 a 2.00 PM Late have 1 poliet dat w e d e All Work for any partial resit. If you feel andre all population has mal distribution. You will for the with you the tons involving hypothesis testing yo of the the o ret of the steps from po 4. You may b e ther ed 2019 Decker 1.2009 specificher r i sche Bock 2 Q025 Hypothesis: Inferences from Dependent Samples page 475 and notes arve The following represents the mean scores on the same set of 5 statistics excams given in Spring 2010 and Fall 2010. Test the claim that the mean scores for the Spring 2010 semester were less than or equal to the mean scores for Fall 2010. Use o = 0.06. Use d e xam score Spring 2010) - (exam score Fall 2010). 15 points Semester Test Test 2 Test 3 Test 4 TE 5 Spring 2010 76. 8502716 7 73 FRI 2010 74.9 50. 7 723098 THE

Answer 1

Let ud denotes the population mean of differnce. To test null hypothesis Ho Md <0.0 against alternative hypothesis H1 :Md > 0.0 Let d denotes the sample mean of difference, sd denotes the sample standard deviation of difference and n denotes the sample size. Here, d = -0.0600, să = 1.3330, sd = 1.1546, n = 5 The test statistic can be written as: Vn(d – 0.0) sd which under Ho follows a t distribution with n-1 df. We reject Ho at 0.05 level of significance if P-value < 0.05 or if tobs > t0.050,n-1 Now, The value of the test statistic = -0.116204 associated degrees of freedom = 4 The critical value = 2.131847 P – value = P(t4 > -0.116204) = 1 - P(t4 5 -0.116204) = 1 – 0.456546 = 0.543454 Since p-value > 0.05 and tobs * tcritical = 2.131847, so we fail to reject Ho at 0.05 level of significance Hence, we can conclude that mean difference is not significantly greater than 0.0

Conclusion : There is enough evidence to support the claim that mean score for the Spring 2010 were less than or equal to the mean score for Fall 2010.