3 Potassum sulite, KSo, contains HSo, which is the anion of the weak polyproticacid sulfurous acid,...
What is the equilibrium constant expression, K i, for the following weak acid? H 2SO 3( aq) H +( aq) + HSO 3 -( aq) Ki = [H2SO3] / [H+][HSO3-] Ki = [H+]2 [SO32-]/ [H2SO3] Ki = [H+]2 [HSO3-]/ [H2SO3] Ki = [H2SO3] / [H+]2 [SO32-] Ki = [H+][HSO3-]/ [H2SO3
1. For each reaction below Classify each acid, base, conjugate acid, and conjugate base as a strong acid, weak acid, strong base, or a weak base. Calculate the value of the equilibrium constant II. I. Determine if these reactions need to be treated as an equilibrium (needing an ICE table) or a stoichiometry problem (assuming the reaction goes essentially to completion) a. F-(aq) H2O() HF(aq) + H3O*(aq) + H2O(1) NH3(aq) + b. NH4 (aq) OH (aq) + H3O*(aq) NH3(aq) +...
Writing Proton-Transfer Equations for Acid-Base Reactions •PROBLEM: Write balanced total and net ionic equations for the following reactions and use curved arrows to show how the proton transfer occurs. –(a) hydriodic acid (aq) + calcium hydroxide (aq) → Give the name and formula of the salt present when the water evaporates. –(b) potassium hydroxide (aq) + propionic acid (aq) → Note that propionic acid is a weak acid. Be sure to identify the spectator ions in this reaction.
21. The titration of 25.0 ml. of an unknown concentration HSO, solution requires 83.6 ml of 0.12 M LIOH solution. What is the molarity of the unknown HSO, solution (in MJ? (Write the balanced reaction first) A. 0.20 M B. 0.40 M C. 0.10 M D. 0.36 M E. 0.25 M 22. Complete and balance the following acid-base reaction. What volume of 0.200 M HCI is required for the complete reaction of 1.00 g of Ca(OH): (FW - 74.10g/mol? Ca(OH)(s)...
This question pertains to the pH of a weak acid/weak base salt combo. For an aq solution of NH4NO2, these are the combinations of reactions that are possible. (1) NH4+(aq) + NO21-(aq) ⇆ NH3(aq) + HNO2(aq)____________K1 = ? (2) NH4+(aq) + H2O(l) ⇆ H3O+(aq) + NH3(aq)_______________Ka = 5.6 x 10-10 (3) NO21- + H2O(l) ⇆ HNO2(aq) + OH-(aq)_________________Kb = 2.2 x 10-11 (4) 2H2O(l) ⇆ H3O+(aq) + OH-(aq)_________________________Kw =1.0 x 10-14 Write the symbolic expression for the equilibrium constants...
Answer
Strong base is dissolved in 715 ml of 0.400 M weak acid (K. 4.73 x10) to make a buffer with a pH of 4.05. Assume that the volume remains constant when the base is added. HA(aq) + OH-(aq) 11,011) +A-(aq) -> Calculate the pka value of the acid and determine the number of moles of acid initially present. Number Number рк,-14.325 0.286mol HA When the reaction is complete, what is the concentration ratio of conjugate base to acid? Number...
the table for problem 5 is attached
S. Consider the weak acids in Table 13.2. Which acid-base pair would be best for a buffer at a pH of: a) 3.5 b) 7.3 c) 10.0 To make a buffer with pH 3.0 from HCHO2 and CHO2: a) what must the [HCHO2]/[CHO2] ratio be? 6. ep b) how many moles of HCHO2 must be added to a liter of 0.139 M NaCHO2 to give this pH? c) how many grams of NaCHO2...
Strong Acids and [H'] (and pH) The pH of a strong acid is the concentration of the strong acid. 1.OM HCI makes 1.OM H. Except H2SO4. Its pH is a little lower than that because: H2SO4(aq) H+ (aq) + HS07 (aq) Strong acids generally have K.>>1. We assume K = . The HSO, is a weak acid: HSO2 (aq) + H+ (aq) + S0 - Ka = 1.2 * 10-2 Weak Acids and [H+] (and pH) These are weak electrolytes....
9) Which one of the following pairs cannot be mixed together to form a buffer solutions A) KOH, HNO2 B) H2S03. KHSO3 C) HONH2, HONH3CI D) NaCI, HCI E) RbOH, HF 10) The Henderson-Hasselbalch equation is acid) acid] A) pH- pKa log basel base] D) pH - pKaobase [acid 11) HA is a weak acid. Which equilibrium corresponds to the equilibrium constant Kp for A- A) A (aq) H30+ (aq) HA (aq) H20 0) B) HA (aq) + OH-(aq) 근...
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Polyprotic acids have more than one proton to donate to water, therefore have more than one equilibrium constant for proton donation. For phosphoric acid, there is a three-step equilibrium: H, PO +H,0 5 H2PO4 + H30* H,PO," +H,0 5 HPO - +H30* HPO 2- +,0 5 PO.- +,0* Kai = 7.11 x 10-3 Ka2 = 6.32 x 10-8 Ka; = 4.5 x 10-13 For all conjugate acid base pairs: K, XKK where K is for the reaction...