Question

A paired difference experiment produced the data given below. Complete parts a through e below. ng = 16 x = 150 $ = 157 x = 7 s2 = 25 a. Determine the values of t for which the null hypothesis 11 - H2 = 0 would be rejected in favor of the alterative hypothesis , H2 <0. Use a = 0.10 (Round to two decimal places as needed.) O A. The rejection region is <t . B. The rejection region ist OC. The rejection region is t> . OD. The rejection region ist ort> b. Conduct the paired difference test described in part a. Determine the test statistic, t= (Round to two decimal places as needed.) Draw the appropriate conclusion. Since the observed value of the test statistic in the rejection region, Ho r ejected. There sufficient evidence to indicate that H1 H2 < ata 0.10 c. What assumptions are necessary so that the paired difference test will be valid? Select all that apply. A. The sample size is large (greater than or equal to 30). B. The population variances are equal. c. The differences are randomly selected. L'D. The population of differences is normal. d. Find a 95% confidence interval for the mean difference Ha- SHOS (Round to three decimal places as needed.) e. Which of the two inferential procedures, the confidence interval of part d or the test of hypothesis of part b, provides more information about the difference between the population means? O A. The hypothesis test provides more information because it gives an interval of possible values for the difference between the population means. O B. The confidence interval provides more information because it shows that there is a difference between the population means. C. The confidence interval provides more information because it gives an interval of possible values for the difference between the population means. CD. The hypothesis test provides more information because it shows that there is a difference between the population means. Question is complete. Tap on the red indicators to see incorrect answers.

Answer 1

a)

B. The rejection region is t< -1.34

b)

test stat t ='(x-μ)*√n/sx=

-5.600

Since the observed value of the test statistic is in the rejection region, Hy is rejected. There is sufficient evidence to indicate that H1-H2 <Data = 0.10

c)

C. The differences are randomly selected. L'D. The population of differences is normal.

d)

for 95% CI; and 15 df, value of t=		2.131
margin of error E=t*std error    =		10.98
lower bound=sample mean-E =		-17.983
Upper bound=sample mean+E=		3.983
from above 95% prediction interval for population mean =(-17.983,3.983)

e)

J.C. The confidence interval provides more information because it gives an interval of possible values for the difference between the population means.