A paired difference experiment produced the data given below. Complete parts a through e below nd = 16-1 = 148 x2 = 152 xd =-4 s -25 a. Determine the values of t for which the null hypothesis μι-μ2-0...
A paired difference experiment produced the data given below. Complete parts a through e below. ng = 16 x = 150 $ = 157 x = 7 s2 = 25 a. Determine the values of t for which the null hypothesis 11 - H2 = 0 would be rejected in favor of the alterative hypothesis , H2 <0. Use a = 0.10 (Round to two decimal places as needed.) O A. The rejection region is <t . B. The rejection...
153 Xd 25 x1-143 2 0 a 100 a. Deterrnirne the values of t for which the null hypothesis H-20 would be rejected in favor of the alternativs hypothesis Round to two decimel pleces as needed.) OA. The rejection region ist O B. he rejection region ist O C. The rejection regionis OD. The rejection region ist b. Conduct the paired difference lest described in part a. Determine the test statistic. 21 or ta Round lo two decnal placos as...
A paired difference experiment produced the following data: nD = 18 x1 = 92 x2 = 95.5 xD = -3.5 sD2 = 21 Determine the values of t for which the null hypothesis, µ1 - µ2 = 0, would be rejected in favor of the alternative hypotheses, µ1 - µ2 < 0. Use α = .10. Conduct the paired difference test described in part a. Draw the appropriate conclusions. What assumptions are necessary so that the paired difference test...
A paired difference experiment yielded the results shown below nd 45 a. Test Ho: μ,-11 against Ha: μd # 11 where μ,-(μι-Hz). Use α:0.01 b. Report the p-value for the test you conducted in part a. Interpret the p-value a. Determine the test statistic The test statistic is (Round to two decimal places as needed.) Identify the rejection region. Select the correct choice below and fill in the answer box to complete your choice (Round to three decimal places as...