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A paired difference experiment produced the data given below. Complete parts a through e below nd = 16-1 = 148 x2 = 152 xd =-

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Answer #1

b.

t = sa/m

t = -4/(25/16)^(1/2)

t = -3.5

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A paired difference experiment produced the data given below. Complete parts a through e below nd = 16-1 = 148 x2 = 152 xd =-4 s -25 a. Determine the values of t for which the null hypothesis μι-μ2-0...
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