A cylindrical rod of 1040 steel having originally 11.4 mm in diameter is cold-worked by drawing...
A cylindrical rod of 1040 steel having originally 11.4 mm in diameter is cold-worked by drawing
(i.e. pulling through a die with a hole smaller than the original rod cross section). The circular
cross section will be maintained during deformation. The deformed steel is desired to have tensile
strength in excess of 825 MPa and ductility of at least 12% EL. The final diameter must be 8.9
mm. Explain how this may be accomplished.
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A cylindrical rod of 1040 steel having originally 11.4 mm in
diameter is cold-worked by drawing...
this all of it !!! 4. Two previously undeformed specimens of the same metal are to...
this all of it !!!
4. Two previously undeformed specimens of the same metal are to be plastically deformed by reducing their cross-sectional areas. One has a circular cross section, and the other is rectangular during deformation the circular cross section is to remain circular, and the rectangular is to remain as such. Their original and deformed dimensions are as follows: Rectangular (mm) Circular (diameter, mm) 125x 175 15.2 Original dimensions 7.5x 200 Deformed dimensions 11.4 Which of these specimens...
4. (a) What is cold work and its significance in material properties. (b) Briefly explain why...
4. (a) What is cold work and its significance in material properties. (b) Briefly explain why cold-worked metals are more susceptible to corrosion than noncold-worked metals. (c) A cylindrical rod of 1040 steel originally 15.2 mm in diameter is to be cold worked by drawing; the circular cross section will be maintained during deformation. A cold-worked tensile strength in excess of 840 MPa was applied. Determine the percent cold work if the final diameter must be 10 mm. [20 pts]
A cylindrical rod of copper having an initial diameter of 16 mm is to be cold worked by drawing such that the cross-sectional area is reduced. It is required to have a cold-worked yield stress of at...
A cylindrical rod of copper having an initial diameter of 16 mm is to be cold worked by drawing such that the cross-sectional area is reduced. It is required to have a cold-worked yield stress of at least 200 MPa and a ductility in excess of 12%; in addition, the final diameter of 11.3 mm is required. Describe the manner in which this procedure may carried out by answering: (10p) Write the yield strength and ductility before cold work. (15p)...
Dura Total: 75 points initial diameter of 25.1 mm is to be cold worked by drawing...
Dura Total: 75 points initial diameter of 25.1 mm is to be cold worked by drawing in order to reduce the (Crigh cctional area such that the final diameter is 22.5mm. Figures 7.19a left) and 7.1e In. Deformation -cold working: A non-cold-worked 1040 steel cylindrical bu 7.19c (right) from the text are provided. 040 60 10 1040 ste Coopar Percent cold work a. Determine the ductility (%EL) and yield strength of the steel rodaner a single drawing process reducing the...
A cylindrical specimen of a cold-worked brass has a ductility (%EL) of 33%. If its cold-worked...
A cylindrical specimen of a cold-worked brass has a ductility
(%EL) of 33%. If its cold-worked radius is 11 mm, what was its
radius before deformation? You may need to use Animated Figure
7.19c.
Percent cold work = 0 Ductility = 0 Ductility (%EL) Brass 1040 Steel Copper 10 60 70 20 30 40 50 Percent cold work
Summer 2 Name: Question 3: (10 points) A cylindrical specimen of cold-worked copper has ductility (%EL)...
Summer 2 Name: Question 3: (10 points) A cylindrical specimen of cold-worked copper has ductility (%EL) of 30%. (a) If its cold worked radius is 6.4 mm, what was its radius before deformation? (b)What are its tensile and yield strengths? 140 120 800 900 1040 Steel 1040 S 700 800 100 120 600 a700 80 100 E 500 600 400 Br Brass 500 300 Capper 40 400 200 Capper 300 20 100 200 10 20 30 40 50 70 10...
A cylindrical car component with 7 mm diameter is to be manufactured. The component is required...
A cylindrical car component with 7 mm diameter is to be manufactured. The component is required to possess a yield strength of at least 700 MPa and an elongation to fracture of at least 11%. For this purpose, you use a cylindrical steel 1040 rod with an initial diameter of 9 mm. The percent cold work cannot exceed 40% during any single cold deformation step in order to avoid cracking. Using the diagram below, describe your manufacturing procedure for this...
3. You are tasked with strengthening a 1040 steel rod via strain hardening. The component's application...
3. You are tasked with strengthening a 1040 steel rod via strain hardening. The component's application dictates a minimum of a 700 MPa yield strength while also maintaining as much ductility as possible. a. What percent cold working would you recommend? What are the associated yield strength and %EL? b. Given a starting diameter of 30mm, what should your diameter be after the prescribed cold working? 1040 Steel SEL Yield streng Mal Duct 400 Cooper 1040 Steel 2001 20 Copper...
Problem 1 (10 pts) It is required to manufacture a 2.5 mm diameter copper rod from...
Problem 1 (10 pts) It is required to manufacture a 2.5 mm diameter copper rod from larger diameter stock by drawing. The rod should have a tensile strength of 300 MPa or more, a yield strength of 200 MPa or more, and ductility of 10% or more. Determine (a) the range of%CW which will allow achieving those properties, and (b) within this range clearly pick a certain%CW and determine the corresponding diameter of the starting stock. yield strength (MPa) tensile...
Problem #1 A cylindrical rod of copper (E 110 GPa) having a yield strength of 240...
Problem #1 A cylindrical rod of copper (E 110 GPa) having a yield strength of 240 MPa is to be subjected to a load of 6660 N. If the length of the rod is 380 mm, what must the diameter be to allow an elongation of 0.50 mm? A cylindrical specimen of some alloy 8 mm in diameter is stressed elastically in tension. A force of 15,700 N produces a reduction in the specimen diameter of 5 10-3 mm. Compute...
this all of it !!!
4. Two previously undeformed specimens of the same metal are to be plastically deformed by reducing their cross-sectional areas. One has a circular cross section, and the other is rectangular during deformation the circular cross section is to remain circular, and the rectangular is to remain as such. Their original and deformed dimensions are as follows: Rectangular (mm) Circular (diameter, mm) 125x 175 15.2 Original dimensions 7.5x 200 Deformed dimensions 11.4 Which of these specimens...
4. (a) What is cold work and its significance in material properties. (b) Briefly explain why cold-worked metals are more susceptible to corrosion than noncold-worked metals. (c) A cylindrical rod of 1040 steel originally 15.2 mm in diameter is to be cold worked by drawing; the circular cross section will be maintained during deformation. A cold-worked tensile strength in excess of 840 MPa was applied. Determine the percent cold work if the final diameter must be 10 mm. [20 pts]
Dura Total: 75 points initial diameter of 25.1 mm is to be cold worked by drawing in order to reduce the (Crigh cctional area such that the final diameter is 22.5mm. Figures 7.19a left) and 7.1e In. Deformation -cold working: A non-cold-worked 1040 steel cylindrical bu 7.19c (right) from the text are provided. 040 60 10 1040 ste Coopar Percent cold work a. Determine the ductility (%EL) and yield strength of the steel rodaner a single drawing process reducing the...
A cylindrical specimen of a cold-worked brass has a ductility
(%EL) of 33%. If its cold-worked radius is 11 mm, what was its
radius before deformation? You may need to use Animated Figure
7.19c.
Percent cold work = 0 Ductility = 0 Ductility (%EL) Brass 1040 Steel Copper 10 60 70 20 30 40 50 Percent cold work
Summer 2 Name: Question 3: (10 points) A cylindrical specimen of cold-worked copper has ductility (%EL) of 30%. (a) If its cold worked radius is 6.4 mm, what was its radius before deformation? (b)What are its tensile and yield strengths? 140 120 800 900 1040 Steel 1040 S 700 800 100 120 600 a700 80 100 E 500 600 400 Br Brass 500 300 Capper 40 400 200 Capper 300 20 100 200 10 20 30 40 50 70 10...
A cylindrical car component with 7 mm diameter is to be manufactured. The component is required to possess a yield strength of at least 700 MPa and an elongation to fracture of at least 11%. For this purpose, you use a cylindrical steel 1040 rod with an initial diameter of 9 mm. The percent cold work cannot exceed 40% during any single cold deformation step in order to avoid cracking. Using the diagram below, describe your manufacturing procedure for this...
3. You are tasked with strengthening a 1040 steel rod via strain hardening. The component's application dictates a minimum of a 700 MPa yield strength while also maintaining as much ductility as possible. a. What percent cold working would you recommend? What are the associated yield strength and %EL? b. Given a starting diameter of 30mm, what should your diameter be after the prescribed cold working? 1040 Steel SEL Yield streng Mal Duct 400 Cooper 1040 Steel 2001 20 Copper...
Problem 1 (10 pts) It is required to manufacture a 2.5 mm diameter copper rod from larger diameter stock by drawing. The rod should have a tensile strength of 300 MPa or more, a yield strength of 200 MPa or more, and ductility of 10% or more. Determine (a) the range of%CW which will allow achieving those properties, and (b) within this range clearly pick a certain%CW and determine the corresponding diameter of the starting stock. yield strength (MPa) tensile...
Problem #1 A cylindrical rod of copper (E 110 GPa) having a yield strength of 240 MPa is to be subjected to a load of 6660 N. If the length of the rod is 380 mm, what must the diameter be to allow an elongation of 0.50 mm? A cylindrical specimen of some alloy 8 mm in diameter is stressed elastically in tension. A force of 15,700 N produces a reduction in the specimen diameter of 5 10-3 mm. Compute...
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