Question

***Turn in this sheet for up to 5 Data points. Record all data in your lab book.*** UNKNOWN NUMBER_ 66 MOLARITY of NaOH_0.0980 M Rough Trial 1 Trial 2 Mass HX (8) NIA Initial NaOH buret reading (ml) 0.46 13 g 1.2 mL 24.1 ml Final NaOH buret reading (mL) Volume NaOH added (mL) 22.9 mL WRITE THE BALANCED CHEMICAL EQUATION FOR THIS EXPERIMENT: Show calculation of: for TRIAL 1 (only) a) moles of NaOH used: b) moles HX titrated: c) molar mass of HX: Record results (round off to 3 significant figures): Trial 1 MM Trial 2 MM = _ NA _ Trial 3 MM = _ NA

please help with a) b) c) and please show the work. thank you!

Answer 1

Kindly rate...

Neutralisation equi. i NaOH(aq) + HX(aq) - NAX (aq) + H₂Oce)! I mol of HX is neutralised by I mol of NGOH. moles of Nach used = moles of HX present. Thus a) moles of Naoh used - molarity (M) x volume used in L = 0.0980m x 0.02296 =0.0022442 mol. 22.9mL X 0.001L E=0.02291 Ime - b. moles of HX titeated a moles of Naoh used = 0.0022442 mol. e). molar mass af HX = molar mass of HX used moles of HX = 0.46139 0.0022442 mol = 205.6 g/mol Thus molar mass of HX = 205.0g/mol. mam