30 6 9 Compute the slope of the line tangent to the 36 Consider the upper...
Consider the parabola y = 7x - x2. Find the slope m of the tangent line to the parabola at the point (1, 6). using this definition: The tangent line to the curve y = f(x) at the point P(a, f(a)) is the line through P with slope m=lim x rightarrow a f(x)-f(a)/x-a provided that this limit exists. m = using this equation: m=lim h rightarrow 0 f(a+h)-f(a)/h m= Find an equation of the tangent line in part (a). y...
Consider the following potential function and the graph of its equipotential curves to the right. Then answer parts a through d. phiφ(x,y)equals=2 e Superscript x minus y Consider the following potential function and the graph of its equipotential curves to the right. Then answer parts a through d. 4(x.y)=2*-y a. Find the associated gradient field F = V p. F=CD b. Show that the vector field is orthogonal to the curve at the point (1,1). What is the first step?...
At the given point, find the slope of the curve or the line that is tangent to the curve, as requested. y + x3 = y2 + 9x, slope at (0,1) 1 OB. NI
At the given point, find the slope of the curve or the line that is tangent to the curve, as requested. y® + x3 = y2 + 11x, tangent at (0,1) 11 O A. y=- 8 11 OB. y=- EX-1 11 O C. y= 6*+1 11 OD. y= *+1
3 TT Find the slope of the tangent line to polar curve r = 7 – 6 sin 0 at the point ( 7 – 6- 2 2 3 TT TT Find the points (x, y) at which the polar curve r = 1 + sin(e), 0 < has a vertical 4 4. and horizontal tangent line. Vertical Tangent Line: Horizontal Tangent Line:
2 The slope of the tangent line to the curve y = at the point (8, is: 1 32 The equation of this tangent line can be written in the form y = mx + b where: m is: bis:
Consider the following. z = x2 + y2, z = 36 − y, (6, -1, 37) (a) Find symmetric equations of the tangent line to the curve of intersection of the surfaces at the given point. x − 6 12 = y + 1 −2 = z − 37 −1 x − 6 1 = y + 1 12 = z − 37 −12 x − 6 = y + 1 = z − 37 x − 6 12 =...
2. Find the slope of the tangent line to f(x, y) 6-x2 + xy - y2 at (4, 2), toward the point (7, 1). Then find the maximum slope and its direction 2. Find the slope of the tangent line to f(x, y) 6-x2 + xy - y2 at (4, 2), toward the point (7, 1). Then find the maximum slope and its direction
yIP is paralle FaPat P df be the point at which f has a local extreme value. Then, dt t-t Let C be expressed parametrically as rit) (x() yit, and let P(ab) (())) This means that Viab)-r (6)Vg(a b) Because r(t) is orthogonal to C. VP) is orthogonal to the line tangent to C at P The gradient is maximized VgP) is orthogonal to C at P because gixy)0 is a level curve Therefore, the two gradients are parallel Explain...
Use implicit differentiation to find the slope of the tangent line to the curve 5x^3 y^2 - 4x^2 y = 1at the point (1,1) m=