Question

How would I try/catch recovery from a format mismatch error? The scanner needs to continue prompting until the user enters a valid number. I know that I would need to try n = kbd.nextInt(); and catch a InputMismatchException and if n<1 or n>100 then I need to print Out of Range Exception. Must be in 1..100. However, I am unsure how to loop all of that. 
Enter a number between 1 and 100 ti Input not a number. Try again java. lang.Exception: Out of Range Exception. Must be in 1..100 110 Enter a number between 1 and 100 456 Enter a number between 1 and 100 67 You entered 67

import java.io.*;
import java.util.*;

public class Lab5
{
        public static void main( String args[] )
        {

                Scanner kbd = new Scanner(System.in);

                System.out.print("Enter a number between 1 and 100 ");
                System.out.printf("You entered %d\n", kbd.nextInt() );

        } //END main
} //EOF

Answer 1

import java.io.*;
import java.util.*;

public class Lab5
{
        public static void main( String args[] )
        {

                Scanner kbd = new Scanner(System.in);
       System.out.print("Enter a number between 1 and 100 ");
       //int n = kbd.nextInt();
       int n;
       while(true)
       {
           try
           {
               n = kbd.nextInt();
               if(n >=1 && n <= 100) {
                   System.out.printf("You entered %d\n", n );
                   break;
               }
               else
                   throw new InputMismatchException();
           }
           catch(InputMismatchException e)
           {
               System.out.print("Format mismatch!!! Reenter a number between 1 and 100 ");
               String s = kbd.next();
               continue;
           }
              
                }

        } //END main
} //EOF