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3. In this problem we shall investigate the intermediate value theorem for derivatives. (a) Differentiate the function f(c)=

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3. ( ($(w) - Sain(6) 40 2 = 0 f(0) = 5 22 8in (1/2) - ces() ato 2-0 f(2) is not continuous at 2000 as. am f(a) does not exipinilarly fao) cannot be local min © f(2. zo and f(an)>, then, ce (2,22) fit, f(o)=0, (a) f(a)= 9(2)-K2, g/22) CK (9 122).

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