Question

Determine the vertical and horizontal displacement at F. Mernber Young's Modulus, E - 200 GPa Member Cross-sectional Area, A-6.25e-4 m2 You must submit your solution in the online short answer dialog box. Your solutions must be supported by your hand-written calculations to receive credit 120 KN F m B 3 m E. m

Answer 1

Real load 120 KN F Member forces 3m Ffc = = - 120 KN 2 Fue - - 120 KN Ø 3m D [other member sorces are zero] 4m Vertical displacement at F Apply unit vertical load at F I KN F Member Lorces = -1 KN ffc for = –1 KN с g TD Ginen, E = 200 Gla - 200 x 100 kor/m2 6.25 * 10-4 A = m2 FF FFC LFC Fee fee Loe Avr = + AE 200X106 x 6.25 X10-9 {(120)=(-1) x3 +(-120) (-1) x3} 0'00576 m mm Dors. 5.76 (down ward)