25.6 grams of FeBr3 reacted with 30 mL of 0.50M H2SO4 solution to produce 15.8 grams...
25.6 grams of FeBr3 reacted with 30 mL of 0.50M H2SO4 solution to produce 15.8 grams of Fe2(SO4)3.
2FeBr3 + 3H2SO4 ---> Fe2(SO4)3 + 6HBr
Identify the limiting reagent, calculate the theoretical yield, and calculate the per cent yield.
Homework Answers
I don't know why this is coming above 100%.
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25.6 grams of FeBr3 reacted with 30 mL of 0.50M H2SO4 solution
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