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Nail Class LINE 9:30 Cher Boxe 73 To a solution of 30.00 mL of 0.204 M Fe(NO3), 60.00 mL of O.116 M Na,S was added. 1) Write,

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Answer #1

1.2 Fe(NO₃)2 (aq) + 3 Nags (ong) - Fez S₂ (S) + 6 NaNO₃(aq) 2. 2 Fe3+ (aq) + 6 Noz (aq) + 6 Nat(aq) + 35€ (aq) → FeS, (s) + 6

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