Question

16) When the frictionless system shown above is accelerated by an applied force of magnitude F. the tension in the string between the DIOCR is (SHOW YOUR WORK AND HOW YOU COME UP WITH YOUR ANSWER) a) 2F b) F c) 2/3 F d) F e) 1/3 F 17) A block of mass 3 kg can move without friction on a horizontal table. This block is attached to another block of mass m by a cord that passes over a frictionless pulley, as shown. If the masses of the cord and the pulley are negligible, what is the magnitude of the acceleration of the descending block? a) o b) g/4 c) g/3 d) 2g/3

Answer 1

for Totes Log In masses. . is same. 1 = Ixa = The free body diagrams for each mass is F= applied force T= tension. The hen he az Acceleration for each Using Neneton's second lane, nass (No friction, herce acceleration T= ixa = a for second mass I 2017 f-T= axa Faza:= 2ata: F = 30 :> a= F/3 but tension .T= a = F/ Ausuer: (e).

n free body dicograme decigrons = Tama. : D m2 (m2g-T) = mai but Tania mag-n, ce = mea. M2=1kg M₂9 . Aus: (b): mit Ma a = 1 g = / 34 t is the acceleration of the descending

Answer 2

Answer is wrong, you are assuming T is the same for the front and back string which it can't be. If we call the string between the blocks T2 the formula should be T2 = 2a, for the whole system we can say F=3a, therefore a = F/3, now that we have F we can add it to T2 = 2a and thei means T2 = 2F/3