Question

2. (1 point) A ball of mass m1-2kg and a block of mass m2-10kg are attached by a lightweight cord that passes over a frictionless pulley of negligible mass, as in figure. The block lies on a frictionless incline of angle 15°. Find the magnitude of the acceleration of the two objects and the tension in the cord

Answer 1

Now tension will be the same every where on the string # the equation for m_2 So m_2 g sin theta - T = m_2 a where a is the acceleration of the string # the equation for m_1 (T - m_1 g) = m_1 a \r\n I have considered two things (i) acceleration same for north masses this is length if on part advantages other part will advance in similar fashion to keep length constant (ii) the mass m_1 going xp if it is the other way around a magnetic will appear m_2 g sin theta - T = m_2 a T - m_1 g = m_1 a rightarrow T = m_1 (g + a) m_2 hg sin theta - m_1 g - m_1 a = m_2 a rightarrow (m_2 g sin theta - m_1 g)/(m_1 + m_2) = a \r\n substituted a = 9.8 times (10 times sin 15 degree - 2)/(10 + 2) m/s^2 = 0.48 m/s^2