Question

Solve using Log not LN

Problems and Essays For the reaction dihydroxyacetone phosphate glyceraldehyde 3-phosphate ΔG"=1.8 kcal/mole What ratio of product/reactant must be maintained in order to keep the reaction going in a forward direction? For the reaction fumarate malate What is the change in free energy when one mole of fumarate reacts to make one mole of 2. K02818 malate under standard conditions?

Answer 1

the formula for delta G = - 2.303 RT Log Keq

Ans. 1. Rearranging the above equation, we get -

Keq = 10^ -delta G/1.36

Keq = 10^ - 1.8 / 1.36

Keq = 10^ 1.32

Keq = 20.89 or 20.9

so a product : reactant ratio of 20.9 : 1 must be maintained in order to drive the reaction forward.

Ans. 2 delta G = - 2.303 RT Log Keq

= - 1.36 log 02818

- 1.36 x 3.45

= - 4.6 Kcal